Question : SQL query to select distinct ID for latest date past June/01/2009 where there are (possibly) more than one occurrence of each ID

I have a table with (to keep this simple) two columns : myID and myDate
MyID is NOT unique: that is, the same ID can occur more than once in the MyID field.
MyDate may be blank in some rows

I'm trying to write a query which gives me only the most recent occurence of any ID with an entry in the MyDate field, where the date is greater than June 01, 2009.

So far I've come up with this code.
SELECT DISTINCT(myTable.[MyID]), myTable.[myDate]
FROM
(
SELECT myTable.[myID],MAX(myTable.[myDate]) AS `latest`
FROM myTable
HAVING myTable.[myDate]>#6/1/2009#
)
;


Here is my sample table.
myID      myDate
      
123      1/20/2004
123      3/18/2009
123      8/16/2009
123      8/17/2009
221      5/22/2006
229      
253      
284      10/19/2009





The query should only give me two rows as a result:
123      8/17/2009
284      10/19/2009

Help?

Answer : SQL query to select distinct ID for latest date past June/01/2009 where there are (possibly) more than one occurrence of each ID

also you may add null condition:

select myid, max(mydate) maxdate
from mytable
where mydate > #6/1/2009# and mydate is not null
group by myid
order by myid