Question : SQL - For Each statement?

StoreID        Score              Date                                   Area
002884      83      2008-06-19 00:00:00.000      4002756
002884      50      2008-04-22 00:00:00.000      4002756
002884      70      2007-12-20 00:00:00.000      4002756
002884      76      2007-06-20 00:00:00.000      4002756
002884      64      2007-01-03 00:00:00.000      4002756
002884      80      2006-03-06 00:00:00.000      4002756
002884      76      2005-08-10 00:00:00.000      4002756
002884      64      2004-09-02 00:00:00.000      4002756
007614      71      2008-04-21 00:00:00.000      4002756
007614      80      2007-12-19 00:00:00.000      4002756
007614      76      2007-07-30 00:00:00.000      4002756
007614      80      2007-01-04 00:00:00.000      4002756
007614      75      2006-12-06 00:00:00.000      4002756
007614      66      2006-08-29 00:00:00.000      4002756
007614      68      2006-04-09 00:00:00.000      4002756
007614      83      2005-08-31 00:00:00.000      4002756
007614      88      2004-09-24 00:00:00.000      4002756

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The above set of data is the result of a query

SELECT StoreID, Score, Date, Area
FROM Structure
WHERE Area IN ('4002756')
ORDER BY StoreID, Date DESC

As can be seen, this is a listing of all the scores of the different restaurants in a particular region.

The following SQL returns only the Store IDs of the set of data.

SELECT DISTINCT StoreID
FROM Structure
WHERE RptOperID IN ('4002756')

StoreID
002884
007614

In this case there are only two stores.

I need to run a query that will return the top 6 results for each restaurant for the data at the top.  Is there a 'for each' type of command?  Or how else would be the best way to accomplish this?

Answer : SQL - For Each statement?

something like this:

select * from
(
select ranking = ranking = dense_rank() over (partition by storeid order by score desc), *
from structure
) a
where ranking <= 6