Question : SQL Select Distinct Results (Complex)

I've got a problem that I can't seem to find a solution of.  I thought the simple way would be to use SELECT DISTINCT, however, I think I need to use a JOIN of some sort, or perhaps a nested query, but no idea really how to build it.   Let me give you a table example, and see if you can come up with a way to query it so I can get the data I need.

tblUsers: fldUser, fldTransaction, fldType

OK, I want a query that will return one user, a DISTINCT list of the transaction types, and the HIGHEST transaction for each type.  i.e., if I'm querying user #1, and the table looks like this:

fldUser            fldType            fldTransaction
1                  1                  1
1                  1                  2
1                  2                  1
1                  2                  2
1                  2                  3
2                  1                  1
1                  3                  1


Then I want to see this as the result:

fldUser            fldType            fldTransaction
1                  1                  2
1                  2                  3
1                  3                  1

I've greatly simplified the idea of the tables I'll be using, but the list I want to return will all be in one table, will limit to one value on one field, needs to be DISTINCT for a second field, and for each record returned, needs to return the highest number of a third field.

Help?

"Z"

Answer : SQL Select Distinct Results (Complex)

SELECT fldUser, fldType, MAX(fldTransaction)
FROM myTable
GROUP BY fldUser, fldType
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